X^2-16x-5120=0

Solution for X^2-16x-5120=0 equation:

X^2-16X-5120=0

a = 1; b = -16; c = -5120;
Δ = b2-4ac
Δ = -162-4·1·(-5120)
Δ = 20736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20736}=144$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-144}{2*1}=\frac{-128}{2}
=-64
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+144}{2*1}=\frac{160}{2}
=80
$